SQL Yoga: SQL SERVER: Read values from Comma Separated variable

May 4, 2009

SQL SERVER: Read values from Comma Separated variable

As we have seen, How to generate Comma separated List in SQL. Today we know, how to get values from Comma separated column.

Many times developers asked, How can I read comma separated values from variable? There are many ways to get solution for this.

Lets discuss about the best way, I think so. We can use XML to read values from comma separated values. XML made our life easy.

Example:

I have one procedure which has one parameter VARCHAR(100), which might contains value like '1,5,6,20'. What I need to do is: I need to update rows contains these ID(1,5,6,20). So We need to make query which will update status of these IDs.

Solution:
I converted this VARCHAR Variable to XML by following way:
SET @xmlIDs =    '<IDs>
<ID>'
+ REPLACE(@str, ',', '</ID><ID>') + '</ID>' +
'</IDs>'



So this statement will generate XML from VARCHAR value as follows:




<IDs>
<ID>1</ID>
<ID>6</ID>
<ID>7</ID>
<ID>8</ID>
<ID>20</ID>
</IDs>



So, Now this is the XML, which can be easily read with SQL SERVER 2005 as:




SELECT x.v.value('.','INT')
FROM @xmlIDs.nodes('/IDs/ID') x(v)



This will give me result set as: ( as separate table)



image



So that’s it, Now I can easily use this result set in my query, to update the rows accordingly.



So my Procedure looks like:




CREATE PROC Test_ReadValuesFromCommaSeparatedVariable
@str VARCHAR(100)
AS

DECLARE @XmlIDs XML

SET @xmlIDs = '<IDs>
<ID>'
+ REPLACE(@str, ',', '</ID><ID>') + '</ID>' +
'</IDs>'

UPDATE TableName
SET Flag = 1
WHERE ID IN(
SELECT x.v.value('.','INT')
FROM @xmlIDs.nodes('/IDs/ID') x(v)
)



So, it is very easy to read values from Comma separated value.



Let me know if it helps you.

6 comments :

Anonymous said...

Hey Tejas,

Its nice work done by you, its very helpful topic for people.

thanks & keep going...

Keyur Patel

Anonymous said...

Thank you for this quick and easy method to search with a list! Very helpful!

Affan said...

Hi..

This is nice..but i needed different output...not like this

Tejas Shah said...

Hi Arfan,

Please find the same query for your expected result mentioned on: http://tejasnshah.wordpress.com/2009/04/08/sql-server-sql-query-to-find-table-dependencies/

DECLARE @SQLYOga VARCHAR(MAX), @xmlIDs XML
SELECT @SQLYoga = 'a1 - 2 Nos, a2 - 530 Nos, a3 - 2 Boxes'
SET @xmlIDs = '
' + REPLACE(@SQLYOga, ',', '') + '' +
''


SELECT x.v.value('.','VARCHAR(100)')
FROM @xmlIDs.nodes('/IDs/ID') x(v)

Affan said...

Hi,
Still i am not able to get my expected result...i having a stored table and having data in a field as

a1- 2nos, a2 -230nos, a3-5nos in a column..i need this column data as
a1 - 2nos
a2 - 230nos
a3 - 5nos

Thanks in advance

Tejas Shah said...

Hi Arfaan,

Can you please send me your query?

Thanks,
Tejas
SQLYoga.com

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